in below document how filename field in java ?
> db.audit.findone({"auditorcomments.filepath":"newaudit6269242818132644222/withoutjs.txt"},{'auditorcomments.$':1}) { "_id" : objectid("573a02dbe4b017e93448707b"), "auditorcomments" : [ { "username" : "c9-security-1_ww@oracle.com", "date" : isodate("2016-05-20t23:59:29.889z"), "filename" : "withoutjs.txt", "filepath" : "newaudit6269242818132644222/withoutjs.txt", "comment" : "test", "bugnumber" : "1234" } ] } i have java code returns null
public string getfilename(string key) { dbcursor cur = audit.find(new basicdbobject("auditorcomments.filepath",key),new basicdbobject ("auditorcomments.$",1)); string test = null; while (cur.hasnext()) { test = (string) cur.next().get("auitorcomments.filename"); system.out.print(test); } return null; }
try this:
public string getfilename(string key) { dbcursor cur = audit.find(new basicdbobject().append("auditorcomments.filepath", "newaudit6269242818132644222/withoutjs.txt")); string test = null; while (cur.hasnext()) { basicdbobject current_object = (basicdbobject) cur.next(); basicdblist auditorcomments = (basicdblist) current_object.get("auditorcomments"); test = ((basicdbobject) auditorcomments.get(0)).getstring("filename"); system.out.println(test); } return test; } 