c++ - Can I define the same function with the same number and type of params in the derived class? -

this question has answer here:

• function same name different signature in derived class 2 answers

is legal (this header files, , .cpp files contain function definitions):

class human { protected:     std::string     m_name;     int             m_age;  public:     human();     void printname() const;     void printage() const; }; 

and re-define same void printname() const; (which not virtual) in derived class.

class student : public human { public:     student();     void printname() const;     void study() const; }; 

what this? not overriding. not overloading too, right? far overloading should have different type or number of arguments (method constant in both places). have done here?

simple answer: yes.

more complex answer: yes, codicil:

student s{}; s.printname();  // call student::printname() const human &h = s; h.printname();  // call human::printname() const on same object 

since methods aren't virtual, compiler call method based on type compiler sees @ point of call.

the printname() method in student override. not virtual override.