What does [int.,int] means in Maple? -


i have code works non linear system equation solver. have trouble command goes this:

newt[0]:=[-2.,20]: 

i don't know dot works there! thought may showing -2.0, there no reason use when default -2 = -2.0.

can me this?

the dot forces float calculations

it not correct default -2 = -2.0. there big difference maple in how calculates: if use -2 calculates exacts (arithmetic expressions) while -2.0 tells maple calculate floats (numerical expressions).

the 2 expressions -2.*sqrt(5) , -2*sqrt(5.) quite different in how maple handles them, if notice float position! first example, square root calculated arithmetically, while in second example calculated numerically!

this can big deal calculations; both regards speed , precision, , should considered when 1 wants complicated computations.


speed example: calculate exp(x) x = 1,2,...,50000. (arithmetic > numerical)

codetools:-usage(seq(exp(x),x=1..50000)):      # arithmetic 
memory used=19.84mib, alloc change=0 bytes, cpu time=875.00ms,  real time=812.00ms, gc time=265.62ms 
codetools:-usage(seq(exp(1.*x),x=1..50000)):   # numerical 
memory used=292.62mib, alloc change=0 bytes, cpu time=9.67s, real time=9.45s, gc time=1.09s 

notice huge difference in memory used. example of when using floats gives worse performance. on contrary, if approximating anyways, numerical approximation faster.

approximate exp(1) (numerical > arithmetic)

codetools:-usage(seq((1+1/x)^x,x=1..20000)):    # arithmetic 
memory used=0.64gib, alloc change=0 bytes, cpu time=39.05s, real time=40.92s, gc time=593.75ms 
codetools:-usage(seq((1+1./x)^x,x=1..20000)):   # numerical 
memory used=56.17mib, alloc change=0 bytes, cpu time=1.06s, real time=1.13s, gc time=0ns 

precision example: precision, things can go very wrong if 1 not careful.

f:=x->(pi-x)/sin(x); limit(f(x),x=pi);           # arithmetic returns 1 (true value) limit(f(x),x=pi*1.);        # numerical returns 0 (wrong!!!)